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h^2+26h+169=0
a = 1; b = 26; c = +169;
Δ = b2-4ac
Δ = 262-4·1·169
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$h=\frac{-b}{2a}=\frac{-26}{2}=-13$
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